【ベストコレクション】 (ab bc ca)^2 964063-(ab+bc+ac)^2
Let us take abc common from (abbcca) then we getabc(c1 a1 b1)⇒abc(a1 b1 c1)Hence, (abbcca) can be expressed as abc(a1 b1 c1)= a 2 b 2 2ab 2bc 2ca Using identity a2 b2 2ab = (a b) 2 We get, = (a b) 2 2bc 2ca = (a b) 2 2c (b a) or (a b) 2 2c (a b) Taking (a b) common = (a b)(a b 2c )A 2 b 2 c 2 = (a b c) 2 2(ab bc ca) = (2 5 3) 2 2(2×5 5×3 3×2) = 100 62 = 38 Answer (2 2 5 2 3 2) = 38 How To Use the (a 2 b 2 c 2) Formula Give Steps? If Math Ab Ca 0 Math Find The Value Of Math Frac 1 A 2 Frac 1 B 2 Ca Frac 1 C 2 Ab Math Quora (ab+bc+ac)^2